2[x-3]+3y=0

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Solution for 2[x-3]+3y=0 equation:


Simplifying
2[x + -3] + 3y = 0

Reorder the terms:
2[-3 + x] + 3y = 0
[-3 * 2 + x * 2] + 3y = 0
[-6 + 2x] + 3y = 0

Solving
-6 + 2x + 3y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 2x + 6 + 3y = 0 + 6

Reorder the terms:
-6 + 6 + 2x + 3y = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 2x + 3y = 0 + 6
2x + 3y = 0 + 6

Combine like terms: 0 + 6 = 6
2x + 3y = 6

Add '-3y' to each side of the equation.
2x + 3y + -3y = 6 + -3y

Combine like terms: 3y + -3y = 0
2x + 0 = 6 + -3y
2x = 6 + -3y

Divide each side by '2'.
x = 3 + -1.5y

Simplifying
x = 3 + -1.5y

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